Question

Simplify:

Answer 1

Man that's a hard one.

Answer 2

\[36a ^{2} \over 7\] times \[5 \over 18a \]

Answer 3

Write the numerator and denominator in terms of its prime factors, and cancel like terms.\[\frac{36 a^2}{7}\cdot\frac{5}{18a}=\frac{\cancel 2\cdot 2 \cdot \cancel 3 \cdot \cancel 3 \cdot 5 \cdot \cancel a \cdot a}{\cancel 2 \cdot \cancel 3 \cdot \cancel 3 \cdot 7 \cdot \cancel a}=\boxed{\dfrac{10a}{7}}\]