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Solve the equations: (4x-6)(2x-5)=0
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x=6/4=3/2 or x=5/2
i think i solved this earlier..
okaeeee . and how would i put it in brackets? and@ arnab09 you did but i wrote the problem wrong :)
{3/2,5/2}
order doesnot matter:)
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Then how would i do this one? 3x^2=6 ?
With brackets i think .
sqart(2, -2)
\[x=\pm \sqrt{2}\]
3x^2-6=o 3(x^2-2)=0 x^2-2=0 then x=\[\pm{\sqrt{2}}\]
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@ koena, bracket is not applicable all time.. :)
Ok :)
Thanks everyone that really helped!
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