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Simplify -3x + 9 ----- -3
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(-3x + 9 over -3)
\[\frac{-3x+9}{-3}=\frac{-3(x-3)}{-3}\]
what is -3/(-3)=?
divide -3 x by -3 and you get x the divide 9 by -3 and you get -3
\[\frac{-3x+9}{-3}=\frac{-3(x-3)}{-3}=\frac{-3}{-3} \cdot (x-3)=1 \cdot (x-3)=x-3\]
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