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Physics 9 Online
OpenStudy (anonymous):

(Newton's Law of Motion) A net horizontal force of 4000 N is applied to a 100 kg car. What will the car's speed be after 10 s if it started from rest?

OpenStudy (anonymous):

\[f=ma\] 4000N=100kg * a a= 40m/s/s \[v=at\] v=(40m/s/s)(10s) v=400m/s

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