Question

suppose that sec(t) =3/2 and that t is in 4th quadrant. find the exact value of tan(t)

Answer 1

that is (sqrt of 13)/2

Answer 2

How did you arrive at this answer?

Answer 3

\[\sec^2t-1=\tan^2t\]
\[\tan^2t=(\frac{3}{2})^2-1\]

Answer 4

\[tant=\frac{\sqrt5}{2}\]\[\tan^2t=\frac{5}{4}\]