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y=(3x^2-12)/(x^2-5x+6) List all the asymptotes Vertical Asymptote: Horizontal Asymptote: Oblique Asymptote: Missing Points:
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\[y=(3x^2-12)/(x^2-5x+6) \]
y= (3x-6)/((x+3)
ali previous question what about oblique asymptote and missing points
3x2 -12 =3(x2 -4)=3(x-2)(x+2) x2 -5x +6 =(x-3)(x-2)
yea already at that step
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now what
vertical asym = -3
There is also a hole at 2
Or missing point
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