Question

If y = x^2 + x, find the value of the differential dy corresponding to a change in x of dx = .1 when x =2 show work please

Answer 1

considering dx = \(\Delta x\) ... hmmm

Answer 2

y=x^2+x
first let's differentiate w.r.t to x
dy/dx=2x+1
now dy=dx(2x+1)
given dx=0.1
x=2
dy=0.1(2*2+1)
dy=0.1(5)
dy=0.5