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OpenStudy (anonymous):
given the total cost function c(x) = .03x^2 + 32x + 4300, find the value of x for which the average cost is a minimum..... show work please
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OpenStudy (anonymous):
complete the square or derivative of the function
OpenStudy (anonymous):
? do you mean apply c(x)/x
OpenStudy (anonymous):
That isnt appearing as a correct answer on my homework
OpenStudy (anonymous):
0.03x^2 + 32x + 4300 is your function, right?
OpenStudy (anonymous):
378.594 is the answer they gave for this problem, yes thats the function
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OpenStudy (anonymous):
x = -533.333 It's either the answer key is wrong or you typed it wrong
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