Question

r^2(cosθrsinθ)=1/2r^2sin(2θ)
how are these equivalent?

Answer 1

\[\text{ recall } \sin(2\theta)=2 \sin(\theta) \cos(\theta)\]
\[\text{ so } \frac{1}{2}\sin( 2 \theta) =\frac{1}{2} \cdot 2\sin(\theta) \cos(\theta)=\sin(\theta) \cos(\theta)\]

Answer 2

ahh..that is what is getting me.. thank you! awesome!!!

Answer 3

np

Answer 4

its the "Double Angle Formula!!!" lol