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please help me solve for x log2(7x + 1) = log2(2 - x)
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Assuming it is "base 2", you have 7x + 1 = 2 - x. Solve for x now.
6x+1 ?
8x +1
7x + 1 = 2 - x 7x + x = 2 - 1 8x = 1 x = 1/8
why a fraction? thanks
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If 8 times x is 1, x has to be a fraction and be equal to 1/8.
thank you. This is still hard for me
1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 1
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