Two rooms in a house are similar rectangles. Room A is 12 ft by 16 ft. The longer side of Room B is 4 ft shorter than twice the length of the shorter side of Room A. What are the dimensions of the second Room B?

Question

anonymous · Answer

Area of room A = 12*16 = 192 square foot.

Dimensions of Room B:
Length = 2*Width - 4

Area of Room B = Width * (2*Width-1) = 192

Solve.

anonymous · Answer

So what would the answer be? would it be 16 * 16
14 * 16
16 * 20
15* 20

anonymous · Answer

You need to solve that equation about to find the width and then the length.

anonymous · Answer

How would I do that?

anonymous · Answer

Solve the following for x:$$\frac{12}{16}=\frac{x}{2*12-4}$$x = 15, room is 15 by 20 ft