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solve the equation x-8sqrtx=-15
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\[x-8\sqrt{x=-15}\]
\[x-8\sqrt{x}=-15\]
yesssss
\[-8\sqrt{x}=-x-15\]
\[(-8\sqrt{x})^{2}=(-x-15)^{2}\]
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\[64x = x ^{2}+30x +225\]
Let sqrt(x) = b b^2 - 8b = -15 b^2 - 8b + 15 = 0 (b-3) (b-5) = 0 b = 3, 5 x = 9, 25
\[x ^{2}-34x + 225 = 0\]
\[(x-9)(x-25)=0\]
x=9 or x = 25
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\[2x ^{3}-8x/4x-x ^{2}\]
can you help me on this?
Factor|dw:1322971074508:dw| the numerator and denominator
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