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sqrt20a^2b
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\[\sqrt{20a ^{2}b}\]
simplify by factoring
\[2a \sqrt{5b}\]
how did you get 5b?
be it is: \[\sqrt{4}a* \sqrt{5}b \] which then give you \[2a \sqrt{5}b\] since we know that the \[\sqrt{4}\] is equal to 2, but the \[\sqrt{5}\] will give us decimals. so we would just leave it as it is...
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20 = 4 x 5
hope you understand :)
got it thanks. sorry so late on replying i was working the problem out.
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