Question

graph the function f(x)=x2-x-2

Answer 1

The coefficient of the x^2 term on the second degree polynomial is positive showing that it is an upward facing parabola

\[x^2-x-2\]factors into
\[(x-2)(x+1)\] Showing that two zeros of the function are found at x=2 and x=-2
-b/2a yields 1/2 showing that a line of symmetry can be found at x=1/2