Question

There is 3,000,000,000 base pairs and it needs to be replicated. The enzyme can replicate 60 base pairs/sec. If replication is finished in 20 mins (1200sec), how many origin of replications are there?

Answer 1

each origin replicates 60 * 1200 = 72000 base pairs
then we need 3000000000/72000=41667 origins of replication

Answer 2

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Answer 3

A = Pert

for t:

60=e^1200sec*k
60=2.718*k
k=22.075

for the origin:

3,000,000,000=Pe1200*22.075
3,000,000,000=Pe^26490
3,000,000,000=P(2.718)
P=

Answer 4

welcome