Help me to graph this please. During the month of February, the depth, d, of snow in inches at the base of one ski resort could be approximated by adding 7 to twice the number of days, t, since January 31st.

Then graph the equation and use the graph to determine the depth of the snow on February 10.

x=2y+7
2, y intercept on (0,7)
y=10
x=2*10+7
V
x= 20+7
x= V
x= 27
Answer: x=2y+7

Question

Help me to graph this please.  During the month of February, the depth, d, of snow in inches at the base of one ski resort could be approximated by adding 7 to twice the number of days, t, since January 31st.

Then graph the equation and use the graph to determine the depth of the snow on February 10.

x=2y+7
2, y intercept on (0,7)
y=10
x=2*10+7
V
x= 20+7
x= V
x= 27 
Answer: x=2y+7

anonymous · Answer

shouldn't this be y = expression in t?

anonymous · Answer

i would have thought it would be 
$$d=2t+7$$ where t is days since jan 31
since feb 10 is ten days later it would be 
$$d=2\times 10+7=27$$ on feb 10

anonymous · Answer

I'm not sure which is why I'm seeking help.  I want to understand graphing.

anonymous · Answer

Eithr way, how do I graph this equation?

anonymous · Answer

if you graph 
$$y=2x+7$$ you will get a line with slope 2 and y intercept 7
you can start by plotting point, where you pick the x value and compute to find the y value
for example if x = 0 then y = 7 so you have (0,7) on the graph. similarly if x = 1 then y = 9 so you have (1,9) on the graph |dw:1323025260123:dw|

anonymous · Answer

when you plot the points and connect the dots you will get something like this http://www.wolframalpha.com/input/?i=y%3D2x%2B7+for++0%3Cx%3C10

anonymous · Answer

Thanks love. I appreciate your help.