Question

Let f''(x)=12x^2+6,f(1)=4,f'(1)=4.

Then f(x) =

Answer 1

6 x+4 x^3 + b = f'(x)

f' (1) = 10 + b = 4
b = -6

f' (x) = 6 x+4 x^3 -6

f (x) = -6 x+3 x^2+x^4 + constant