Question

Solve for x and I need to see the steps
x^2e^-x-xe^-x-12e^-x=0

Answer 1

factor out e^-x\[e^{-x}(x^2-x-12)=0\]

Answer 2

\[x^2-x-12=0\]

Answer 3

\[(x-4)(x+3)=0\]

Answer 4

Let e^-x be b

bx^2 - bx - 12b = 0

b (x^2 - x - 12) = 0

b ( x + 3) ( x - 4) = 0

x = -3, 4