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L{e^(3t) - U(t-2)*e^(3t)} Laplace this sucker.
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step function , eh
1/(s-3) is first term now second term u(t-2) e^3(t-2)e^6 e^-2s e^6/s-3
where does the e^6 come from?
because it is u(t-2) I had to write e^3t as e^(3(t-2)+6) = e^3(t-2) e^6
OHH thank you.
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I have a test this thursday
no way. mine's tomorrow. freaking out lol
did you guys do fourier series?
nope. this was the last thing we learned. differential equations?
lucky as hell
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i know right!
final is 40% which is freaking me out also
you answered my question. you'll be ok.
lol, I hope so
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