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Solve. 3x2 = 33x + 24
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3x^2
first you can bring it all to one side and then just solve for the zeros using the quadratic formula
\[1/2 (11 \pm 3 \sqrt{17})\]
so your equation should look like this: 0=-3x^2 + 33x + 24
the quadratic equation is:\[-b \pm \sqrt{b ^{2}-4ac}\over 2a\]
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in this case a= -3 b= 33 c= 24
so plug them in to the equation and see what you get!
Thank you!
no prob, good luck!
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