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Mathematics 12 Online
OpenStudy (anonymous):

whats the simplest form of :4|x-1|-16<0

OpenStudy (mathteacher1729):

kclay, it's more or less the same as before. You can divide both sides by 4. :)

OpenStudy (mertsj):

Add 16 to both sides and the divide both sides by 4. You should get 4|x-1| <16 and then |x-1| < 4

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