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solve -3sin(x)^3=0 (** sin is cubed)
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\[-3\sin^3(x)=0\iff \sin(x)=0\]
so \[x=k\pi, k \in \mathbb Z\]
Uhm... what is k suppose to be?
any integer
\[k=...-3,-2,0,1,2,...\]
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