Question

evaluate the definite integral [0,a] xsqrt(x^2+a^2)dx (a>0)

Answer 1

x^2 + a^2 = t

use this :)

Answer 2

still not quite sure what to do

Answer 3

Hmm substitution

Answer 4

x^2 + a^2 = t
2x = dt/dx
dx = dt/2x

Answer 5

now you can do it just put it on paper

Answer 6

you awarded me my 3,500th medal :)