Question

a) Solve 2x^2=14
b) Find the x-intercepts of f(x)=2x^2-14

I'll post the graph.

Answer 1

\[2x²=14\]\[x²=7\]\[x=\pm \sqrt{7}=\pm0.707\]

x intercept mean y=0
\[f(x)=0\]\[0=2x²-14\]
then u will get the same answer as above for x value

so x-intercept coordinate is:
(-0.707,0) and (0.707,0)