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OpenStudy (anonymous):
find 2 positive angles Q in degree for which: a) cos Q= sqr 3/2 b) sin Q= -sqr2/2
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OpenStudy (mertsj):
You should recognize these values as belonging to the two special triangles. The cos of thirty degrees is sqrt3/2. Could also be in quadrant IV in which case it would be 330 degrees. The sin is negative in quadrants III and IV and the reference angle is 45 degrees. So the angle could be 225 degrees or 315 degrees.
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