Question

Find the most general antiderivative. See attachment.

Answer 1

You want to find the anti-derivative of the integral or the integrand?

Answer 2

Integral please. :X

Answer 3

first rewrite the integrand as
\[\frac{1}{\sin^2(x)}=csc^2(x)\] and then think of what function has this as a derivative

Answer 4

Um, -cot(x)+c?

Answer 5

\[\frac{\frac{1}{a}}{\frac{a}{a}-a}=\frac{1}{1-a^2}\] by algebra
replace a by cosine and get
\[\frac{1}{1-\cos^2(x)}=\frac{1}{\sin^2(x)}=\csc^2(x)\]
anti derivative of cosecant squared is - cotangent

Answer 6

yeah you got it!

Answer 7

Hoorah! :D thanks.

Answer 8

yw