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find all solutions for 2cosx sinx-cosx=0
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we can factor out a cosx
cos(x) (2sin(x)-1) = 0 when cos(x) = 0 when 2sin(x) = 1
these trigs for "all solutions" tend to have to have a n*pi or some such in it to account for the periodicity
0,2pie
i take it that means we got an interval of 0 to 2pi :)
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ya
cos(x) = 0, when we are at 90 and 270 degrees sin(x) = 1/2 when x= 60 and 120 if i remember it right
sin is 30 and 150 .... those always blur together for me
but the answ are pie/6,pie/2,5pie/6,3pie/2
yeah, convert the degrees to radians and your set
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|dw:1323119024078:dw|
can u plz give me the answer in radians
y ai got u thanks
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