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Mathematics 15 Online
OpenStudy (ksaimouli):

tanxsin^2x=tanx

OpenStudy (ksaimouli):

find all the solutions

OpenStudy (mertsj):

tanxsin^2x - tanx=0 tanx(sin^2x-1)=0 tanx=0 or sin^2x-1 =0

OpenStudy (mertsj):

If tan x =0 then x = 0 or 180 If sin^2x -1=0 sin^2x = 1 and sinx = 1 or -1 and x = 90 or 270

OpenStudy (mertsj):

If you want ALL solutions you need to add k(360) to all answers

OpenStudy (ksaimouli):

ok but the answer 0,pie

OpenStudy (mertsj):

yep if you want it in terms or pi then 0, pi/2, pi, 3pi/2 +2kpi or you could say 0 +kpi/2

OpenStudy (ksaimouli):

\[\tan^2=3\]

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