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OpenStudy (ksaimouli):
sin^2x-2sinx=0
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OpenStudy (anonymous):
a^2 - 2a = 0 a(a-2) = 0
OpenStudy (jamesj):
\[ \sin x ( \sin x - 2 ) = 0 \] Hence one of the two terms must be zero
OpenStudy (amistre64):
eww, sin(x) = 2?
OpenStudy (jamesj):
No, that's the trick in this question obviously
OpenStudy (amistre64):
;)
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