Question

(2-i)^2

Answer 1

We have the formula for (a-b)^2 as =a^2-2ab+b^2, so applying that we will get....4-4i-1=3-4i

Answer 2

(2-i)(2-i)

4 -2i - 2i + i^2

i^2 - 4i + 4

use quadratic formula or factorise