Question

parametric equations - find the arc length of x=t^2 , y=4t^(3)-1 on the interval [-1,1]

please help

Answer 1

Sqrt[(dy/dt)^2 + (dx/dt)^2]

integrate from -1 to 1

Answer 2

I keep getting zero and that isn't correct...

Answer 3

\[\int_{-1}^1 \sqrt{4 t^2+\left(12 t^2\right)^2} \, dt\]

Answer 4

\[\frac{1}{27} \left(-1+37 \sqrt{37}\right)\]

Answer 5

I dont understand how you are getting that.....

Answer 6

what part did you get stuck?

Answer 7

how are you doing the u substitution?