Question

evaluate: 2sinxcosx-cosx / 1-sinx+sin^2x-cos^2x

Answer 1

\[2sinxcosx-cosx \over 1-sinx+\sin ^{2}x-\cos ^{2}x\]

Answer 2

how did he do that a long __________________ line? =)

Answer 3

over

Answer 4

\[\cos(x)[2\sin(x)-1]\over[\cos ^{2}(x)+\sin ^{2}(x)+\sin ^{2}(x)-\cos ^{2}(x)]\]

Answer 5

=\[\cos(x)[2\sin(x)-1]\over[2\sin ^{2}(x)-\sin(x)]\]

Answer 6

=
\[\cos(x)[2\sin(x)-1]\over \sin(x)[2\sin(x)-1]\]

Answer 7

= cot(x)

Answer 8

in the denominator of my first post there should be also a -sin(x)

Answer 9

a ship started sailing S 42'35' W at the rate of 5kph. after 2 hours,ship B started at the same port going N 46'20' W at the rate of 7 kph.after how many hours will the second ship be exactly north of a ship A? can some answer this

Answer 10

correct = cot(x)