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OpenStudy (anonymous):
analysis shows that a metal oxide has the emprical formula M(0.96)O(1.00) . calculate the % of M(II) and M(III) ions in the crystals
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OpenStudy (anonymous):
one is M(II) 96 % and other is 4 % to determine which quantity is higher u need to give the metal ....i think its Fe ...hence
OpenStudy (anonymous):
M(II) ion: 88% M(III) ion: 12%
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