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A triangle has an area of 15 in2, and two of the sides of the triangle have lengths 5 in. and 7 in. Find the angle included by these two sides. (Assume the angle is acute. Round your answer to one decimal place.)
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15 = A = (1/2)(5)(7)Sin Theta Sin Theta = (2)(15)/ (5)(7) = 30/35 = 6/7 How do I get degrees?
in your calculator,theres somewhere \[\sin ^{-1}\] ,just type \[\sin ^{-1}\](6/7) to get your answer
Oh... Thanks! I forgot to use the inverse.
I got 59 degrees btw
yes
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