Question

Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes through the point (0, 2).






A.

y = 5x + 2





B.

y = -2/5x + 2





C.

y = 2x + 5





D.

y = 1/2x + 5

Answer 1

given line
y=5/2x-2
standard form of line y=mx+c
where m=slope
comparing standard form to the given line
we get slope m=5/2
we have to find the line which is perpendicular to this one let its slope be m1
m1*m=-1
m1*5/2=-1
m1=-2/5
so its equation is
y=-2/5x+c
we have to find c?
it passes through (0,2)
put x=0 y=2 to find c
2=0+c
so c=2
y=-2/5x+2
option B