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OpenStudy (anonymous):
The width of a rectangle is 2ft less than the length. The area is 3ft^2. find the length and width. if you just show me how to get started please
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OpenStudy (diyadiya):
let l be the length
width =l-2
a= l * w
3= l(l-2)
OpenStudy (anonymous):
i still cant come up with the formula
OpenStudy (diyadiya):
l^2-2l-3=0
OpenStudy (diyadiya):
(l-3)(l+1)=0
OpenStudy (diyadiya):
should i continue ?
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OpenStudy (anonymous):
yea...im just reading to see how to come to a completion for the future
OpenStudy (diyadiya):
l-3 =0 l+1=0
l=3 l=-1 (length cant be negative)
so length = 3
OpenStudy (diyadiya):
width= length -2
=3-2
=1
OpenStudy (anonymous):
Solve the following for L and w:\[\{w\text{ = }L-2,L* w\text{ = }3\}\]
OpenStudy (anonymous):
ok so it cant never be negative
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OpenStudy (anonymous):
if my area is 3^2 so what my width is 1?
OpenStudy (anonymous):
The solution is\[\{\{L\to -1,w\to -3\},\{L\to 3,w\to 1\}\} \]The positive solution is the one that makes physical sense.
OpenStudy (anonymous):
length =3 width = 1
OpenStudy (anonymous):
Correct. Thank you for the medal.
OpenStudy (anonymous):
you are welcome...i appreciate the help from all..hopefully I will get better so I can help someone
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