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Hi e1:)...pls I need help with: write an equation of the line containing the specified point & perpendicular to the indicated line (4,-2) x=1
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well, what line is perp to "x" ? any guesses?
no, I'm sorry
|dw:1323195776287:dw| the trick is on noticing the equation itself; and this one is a favorite to trick up on
|dw:1323195852596:dw|
you got that right, I keep reading the material over and over
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the perp line to a an x= equation is a y= equation
given the point: (4,-2) we see that y=-2 and that is our equation really. y = -2
thank you amistre64 I need to look at this harder, but I'm sure you are right
good luck with it :)
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