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simplify: x^2 - 16x + 64 over x^2 - 64
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lolx easiest
answer is (x-8) over (x+8)
\[\frac{x^2-16x+64}{x^2-64}= \frac{ \cancel{(x-8)}(x-8)}{\cancel{(x-8)}(x+8)}\]
wow lalaly ur work is soo organised :P
Thank you all! :D Sorry, I'm not too good at algebra...
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=)
honey u r gud at nthin :D
haha i know no need for the reminder
hehe
lol maybe i shouldn't have given you a medal hon :P
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haha u have given now so no choice back :D
i know >.<
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