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OpenStudy (turingtest):
a) this is not physics
b)what do you get upon factoring this? we just did these together...
OpenStudy (ksaimouli):
i got sinx=0 and sinx=2
OpenStudy (ksaimouli):
and radians for sin=0 is pie and2pie
OpenStudy (turingtest):
you phrase our answers strangely, so it is difficult to see whether you have the correct answer...
I assume you got to
\[\sin^2x-2\sin x=0\to \sin x(\sin x-2)=0\]which as you said means\[\sin x=0\]and \[\sin x=2\]
1) for what values of x is sinx=0
2)for what values of x is sinx=2
?
OpenStudy (turingtest):
*should be OR sinx=2
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OpenStudy (turingtest):
so again...
1) for what values of x is sinx=0
2)for what values of x is sinx=2
OpenStudy (ksaimouli):
absaluetly i got that after taht i am confused
OpenStudy (turingtest):
you mean that you don't know for what x we have sinx=0 ?????
OpenStudy (ksaimouli):
sin=2
OpenStudy (turingtest):
that's the only problem for you?
when does sin x=2 ?????
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OpenStudy (ksaimouli):
i dont know in unit circle it is not there
OpenStudy (turingtest):
that's because \[\sin x \le1\]so the answer is NEVER!
which means we only need to consider when \[\sin x=0\]so x=?