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Solve 4|x-3|<8
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|x-3| < 2 x-3 < 2 and x -3 > -2 Solve both. =)
okay, with this problem you are going to first distribute . That leaves you with |4x - 12| <8 . To get rid of the absolute value symbols, just make everything in there positive. Therefore it will now be : 4x + 12 < 8 . You subtract 12 from each side which gives you 4x < -4 . Then you divide by 4 which gives you x < -1 .
4|x - 3| < 8 or 4|x - 3| < -8 4x - 12 < 8 4x < 8 + 12 4x < 20 4x / 4 < 20 / 4 x < 5 or 4x - 12 < -8 4x < -8 + 12 4x < 4 4x / 4 < 4 / 4 x < 1 remember to click good answer
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