Question

solve by factoring and using the principle of zero products.

1.) 3x^2-27x+60=0
2.) x(x-1)=12

Answer 1

1) (3x - 12)(x -5) = 0
x = 5, 4

Answer 2

2)(x - 4)(x + 3) = 0
x = 4, -3

Answer 3

ty :)

Answer 4

would be easier to factor if you wrote
\[3x^2-27x+60=0\]
\[3(x-9+20)=0\] first