Question

simplify completely 2x^2+20x+32
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x^2-2x-80

Answer 1

numerator:
2x^2+20x+32
=2(x^2 +10x +16)
=2(x^2 + 8x + 2x +16)
=2(x(x+8)+2(x+8))
2(x+2)(x+8)
denominator:
x^2-2x-80
=x^2 -10x + 8x -80
=x(x-10)+ 8(x-10)
=(x-10)(x+8)

so,
2(x+2)(x+8)
------------
(x-10)(x+8)

=
2(x+2)
-------
(x-10)