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given the values of x and y, find an equation of variation in which y varies directly as x. y=400, when x=110
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y = k x where k is constant 400 = k 110 k = 40/11 so, y = 40/11 x 11y=40x
i have x=3.64y y=3.64x y=0.28x x=290y
\[\frac{40}{11}\approx3.64\]
across...is right
so y=3.64x?
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yup
hey across
on the slope question tht answer seems too easy?
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