Question

If a pro basketball player has a vertical leap of about 20 inches, what is his hang time? Use the hang-time function V=48 T^2

His hang time is ? seconds.
(Simplify your answer. Type an integer or a decimal. Round to the nearest tenth.)

Answer 1

Given: V = 20 inches
and V = 48 T^2
To find the time T, substitute V = 20
So it becomes 20 = 48 T^2
T^2 = 20/48
= 5/12
Taking square root on both sides , we get,
T = Sqrt(5/12)
T = 0.6457553
Rounded up to the nearest tenth, we got
T = 0.6

Answer 2

So the answer is 0.6 seconds?

Answer 3

Got it!!! THX!! ^_^