Question

secx cscx=tanx+cotx solve only one side lhs and rhs should be euall plz explain how u did dem=nomenator euall

Answer 1

secx cscx = 1/cos x * 1/ sin x = 1 / sinx cosx
tanx + cot x = sinx / cosx + cosx / sin x
= sin^2 x + cos^2 x / sin x cos x
= 1 / sinx cos x

so secx cscx=tanx+cotx

Answer 2

no u should get both the equations equall rhs and lhs

Answer 3

what i've done is shown that lhs = 1 / sinx cos x
and rhs = 1/ sinx cos x

therefore lhs = rhs

Answer 4

u should only work one side

Answer 5

sin x / cos x + cos x / sin x
( sin ² x + cos ² x) / (cos x sin x)
1 / (cos x sin x)
(1/cos x) (1 / sin x)
sec x cosec x

RHS
sec x cosec x

LHS = RHS

Answer 6

its like saying if x = a and y = a
then of course x = y

Answer 7

well both proofs are correct - yours and mine