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(x+1)(x-5)=-6
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x^2 -4x - 5 = -6 x^2 - 4x + 1 = 0
So thats the answer?
No you need to solve for x using the quadratic formula
solve both doing that?
I am very lost on this one and i have 2 minutes to answer the question
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\[2 \pm \sqrt{3}\]
this is the answer you should have told me the answer before the question so I can just give you the answer
Ok so did I have to do the quad formula on both?
Okay thank u
I have 2 more if u have a minute
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ask the question from the left side and i will answer it as soon as you post them
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