Question

solve 3x^2+4x+5=0

a.-10+-i√22/3
b.-2+-i√11/3
c.-2+-i√22/12
d.-2+-5i√11/3

Answer 1

b.(-2+-i√11)/3

Answer 2

can you show me the steps please?

Answer 3

3x^2+4x+5=0
Use the quadratic equation:
a=3, b=4, c=5
x=(-b+-sqrt(b^2-4ac))/2a
=(-4+-sqrt(4^2-4*3*5))/(2*3)
=(-4+-sqrt(44))/(6)
=(-2+-sqrt(11))/3