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OpenStudy (anonymous):
solve 3x^2+4x+5=0 a.-10+-i√22/3 b.-2+-i√11/3 c.-2+-i√22/12 d.-2+-5i√11/3
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OpenStudy (mathmate):
b.(-2+-i√11)/3
OpenStudy (anonymous):
can you show me the steps please?
OpenStudy (mathmate):
3x^2+4x+5=0 Use the quadratic equation: a=3, b=4, c=5 x=(-b+-sqrt(b^2-4ac))/2a =(-4+-sqrt(4^2-4*3*5))/(2*3) =(-4+-sqrt(44))/(6) =(-2+-sqrt(11))/3
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