Question

find the ordered pair for the ertex.

y+x^2-14x+51

Answer 1

y=x^2-14x+51

Answer 2

Given \(ax^2 + bx + c\) ^^

Answer 3

sorry gents, just want the answer, this is my last question for this entire class

Answer 4

Understandable, but not the way I roll, sorry ;) Someone else'll have to sweep in.

Answer 5

no problem shadow, take care

Answer 6

you gotta do it urself :)

Answer 7

bye saso, there is a nice lady below me who needs help, move along

Answer 8

seriously u don't tell me where to look or who to help :) thank you for ur concern :D

Answer 9

rude

Answer 10

As a side note, you may want to try Wolfram Alpha.

Answer 11

i have tried it, too complicated

Answer 12

(7, 2)

Answer 13

Really? I just typed “vertex of y=x^2-14x+51” into it and it gave me the answer ;)

Answer 14

ah, 0,-7 thank you iran

Answer 15

if you want answeres... wolfram alpha is there for ya... if u come here, get ready to do part of the work, i'm not ur calculator ;)

Answer 16

you can also use a TI-89, solve for the derivative equated to 0, and then evaluate the original expression at x = the solution for the derivative equal to 0

Answer 17

no one asked you to be saso, in fact, i don't remember saying anything about you in my questions

Answer 18

sasogeek—I think you've made your point. bhruifafn—likewise, I think you've made your apathy evident.

Answer 19

Ok I will show you how to derive a simple formula for finding the vertex
\[ax^2+bx+c=a(x^2+\frac{b}{a}x)+c=a(x^2+\frac{b}{a}x+(\frac{b}{2a})^2)+c-a(\frac{b}{2a})^2\]
\[=a(x+\frac{b}{2a})^2+c-a \frac{b^2}{4a^2}\]
\[=a(x+\frac{b}{2a})^2+c-\frac{b^2}{4a}=a(x+\frac{b}{2a})^2+\frac{4ac-b^2}{4a}\]
Vertex is
\[(-\frac{b}{2a},\frac{4ac-b^2}{4a})\]

Answer 20

lol thank you mother shadow

Answer 21

Mm. No problem. Just remember this mother has suspension powers. Though it sounds like you won't be needing help anymore after this fella.

Answer 22

mother shadow lol

Answer 23

suspend away mother dearest

Answer 24

this is it for me :) thanks to everyone who helped!!

Answer 25

7,2 or 0,7?

Answer 26

(7, 2)

Answer 27

thank you shadowfiend. the help was appreciated, if you have so much power you should suggest it be known that the person asking the question will be required to do work, not just ask for answers

Answer 28

and that harassment is rampant

Answer 29

Harassment is something we're working on. We're also working on reining in some of our more... Erm... Emphatic helpers, and making it clear that if they don't want to give out answers they should move on rather than harass.

Answer 30

\[(-\frac{-14}{2(1)},\frac{4(1)(51)-(-14)^2}{4(1)})=(7,2)\]
you could get what shadow got just by plugin the answer into this formula for the vertex i gave you

Answer 31

thank you myininaya

Answer 32

and shadow that sounds wonderful. take care. goodbye openstudy, hopefully forever, but possibly not. time will tell :). mwuah. it's been real.

Answer 33

come on dont leave we'll all miss you

Answer 34

hmm... what's the Aesop we can draw from all this?

Answer 35

The moral of the story is, just because you see a hot girl avatar...


Doesn't necessarily mean you're dealing with a girl ;)

Answer 36

bingo

Answer 37

lol
what?

Answer 38

Well, ill miss the banter, is what i meant

Answer 39

study complete. you get much more help if you put up a pic of a hot girl, and sudo act like one

Answer 40

Hehehe. You would get along swell with our CEO.

Answer 41

you have all helped my senior thesis. thank you for participating in my abnormal psych study.

Answer 42

I don't go where the hot girls are.

Answer 43

I should have left my girl avatar on :(

Answer 44

I just go to a question I want to answer.

Answer 45

sure

Answer 46

you didn't answer my pseudo-inverse question :(

Answer 47

not what i have found out, you are 82% more likely to answer my question because of the arousing pic, than the normal owl

Answer 48

I looked at it, but that requires more brain power than I have right now.

Answer 49

and it took someone in the know to out me.

Answer 50

let me see your data on that

Answer 51

hmm maybe JamesJ could help me with it when he has time.

Answer 52

it's basic empathy

Answer 53

no one helps the dirty bum, but the damsel in distress?

Answer 54

and i wondered why no one was helping me

Answer 55

Indeed. I must say, too, it was a well-picked username. Seemed like a perfectly viable username of Arabic origin, with a perfectly plausible Arabic avatar.

Answer 56

ching ching, thank you shadow

Answer 57

but i couldn't beat you

Answer 58

wanna know the best part shadow?

Answer 59

I have insider info. Doesn't count ;)

Answer 60

I don't even know what to type.
I'm so confused.

Answer 61

I was following the crowd not the pretty picture.

Answer 62

Try me next shadow? what do you know about me?

Answer 63

if you take bhruifafn and take every other letter, you get

b r i a n
h u f f

my real name, male origin.

Answer 64

Shadow knows all, tbh.

Answer 65

i am

Answer 66

it worked, the response time to my question was cut almost in half

Answer 67

The psychologista 8-) A'ight, time to go fix some bugs hehe. Thanks for the entertainment.

Answer 68

thanks shadow. take care man.

Answer 69

It was never about the golden goose

Answer 70

I presume

Answer 71

no i didn't, my class/thesis is complete

Answer 72

Brian - this is awesome stuff. Would you mind sending me a copy of the thesis once you've turned it in and gotten your A :)

Answer 73

if i could give any advice, it would be make a female name and female avatar, people jump all over your questions

Answer 74

i suppose i cold do that chris

Answer 75

Well, not so awesome in that you tricked your fellow peers - but this speaks of greater biases, even within an altruistic community

Answer 76

Don't include me in your statistics. I was just following the crowd. serious stuff.
How do you know the others weren't doing the same?

Answer 77

well i agree, but the people in the know (shadowfiend) saw i was a male, because i put my sex as male in beginning

Answer 78

i don't know that myininaya. it's also about the level of help given, when i was male i was expected to know more, when female people walked me through more and more willing to just give me the answer.

Answer 79

Here's an idea for your next thesis:subjects with names that are egregiously long and complicated, and with black male avatars do not get their questions answered as adequately as the female ones do :-P

Answer 80

nope, just fun om

Answer 81

lol i love it ag

Answer 82

As a side note, I didn't use any male/female data. You said something (I forget what at this point) that made me rethink, and I have access to your email. That was sufficient in this case.

Answer 83

I have given tons of people detailed answers without looking at their pic.

Answer 84

the ends justify the means shadow

Answer 85

well myininaya you are the outlier, always one or two statistical misfits

Answer 86

myin - everyone knows you help everybody without bias =). don't worry about anyone drawing conclusions about individuals - you weigh equally on both sides.

Answer 87

thank you thats all i wanted to hear :)

Answer 88

lol i am not including any names in this at all, just numbers

Answer 89

can i see your data? or is it priviate?

Answer 90

even if i was, it's like taking a photo in public, this is a public domain and anything you say/do here can be recorded

Answer 91

private for now lagrange

Answer 92

here meaning "internet"

Answer 93

Brian - please do not share any personally identifiable information/analysis - generally studies do not allow so (at least for journals). Aggregate analysis that you've mentioned is fair game.

Answer 94

which I understand was your intent

Answer 95

exactly chris

Answer 96

The admins do, yes.

Answer 97

i have some morals

Answer 98

up to the point to get me an a