Question

guys help me !!!
2x+3y=9
3x+2y=9

Answer 1

0

Answer 2

\[3y=9-2x=> 3y=-2x+9=> y=\frac{-2}{3}x+3\]
\[2y=9-3x =>y=\frac{-3}{2}x+\frac{9}{2}\]

set them equal and solve for x
\[\frac{-2}{3}x+3=\frac{-3}{2}x+\frac{9}{2}\]
\[\frac{-2}{3}x+\frac{3}{2}x=\frac{9}{2}-3\]
\[\frac{-4+9}{6}x=\frac{9-6}{2}\]
\[\frac{5}{6}x=\frac{3}{2} => x=\frac{3}{2} \cdot \frac{6}{5}=\frac{6}{2} \cdot \frac{3}{5}=3 \cdot \frac{3}{5}=\frac{9}{5}\]
now you can find y by plugin' the x we just found

Answer 3

\[y=\frac{-2}{3}(\frac{9}{5})+3\]