Need help with integral: I know I am supposed how I am supposed to use partial fractions, but the proffesor did it, I think she got it wrong, I want to confirm, but maybe I am wrong

(x-8) / (x^3 -4x^2 + 4x) dx

Question

Need help with integral: I know I am supposed how I am supposed to use partial fractions, but the proffesor did it, I think she got it wrong, I want to confirm, but maybe I am wrong

(x-8) / (x^3 -4x^2 + 4x) dx

amistre64 · Answer

may have to use partial fraction decomp

amistre64 · Answer

the denom factors to x(x-2)^2

anonymous · Answer

then you put them A/ X + B/(X-2) + C/(X-2)^2  RIGHT?

amistre64 · Answer

yep

amistre64 · Answer

x-8 = A(x-2)(x-2) + Bx(x-2) + Cx


when x = 0

-8 = A(4); A = -2
.................................
when x = 2

-6 = C(2); C = -3

and so on

anonymous · Answer

Ooh ok I think I got it from here. Than you :)

amistre64 · Answer

youre welcome :)